(Part 2)
(Part 2)
Line 15: Line 15:
 
This is <math>x(t)=e^{-t}cos(20t)</math> as the nonperiodic signal.
 
This is <math>x(t)=e^{-t}cos(20t)</math> as the nonperiodic signal.
 
[[image:ctsignal3.jpg|300px|frame|center]]
 
[[image:ctsignal3.jpg|300px|frame|center]]
 +
 +
 +
I haven't played around with matlab enough to know how to create the signal need with my own code, I used the same code that Ben Laskowski used:
 +
 +
----
 +
"y=zeros(size(x));
 +
 +
for count=1:period/delta:(nperiod+8)*period/delta
 +
    y(1,count:size(y,2))=y(1,count:size(y,2))+f(1,1:size(y,2)-count+1);
 +
end
 +
 +
plot(x,y)"
 +
 +
----
 +
 +
[[image:ctsignal4.jpg|300px|frame|center]]

Revision as of 15:13, 12 September 2008

Part 1

Choose the signal $ x(t)=cos(t) $ which is periodic.

Sampling ever interger yields

This is $ x[n]=cos(n) $

but sampling at a frequency of $ \pi/4 $ yields

This is $ x[n]=cos(\pi/4n) $

Part 2

This is $ x(t)=e^{-t}cos(20t) $ as the nonperiodic signal.


I haven't played around with matlab enough to know how to create the signal need with my own code, I used the same code that Ben Laskowski used:


"y=zeros(size(x));

for count=1:period/delta:(nperiod+8)*period/delta

   y(1,count:size(y,2))=y(1,count:size(y,2))+f(1,1:size(y,2)-count+1);

end

plot(x,y)"


Alumni Liaison

EISL lab graduate

Mu Qiao