(New page: == part a == it can't be a time invariant because output is not same. <math>X_k[n] = \delta[n-k]</math> <math>\delta[n-k]\rightarrow time delay\rightarrow\delta[n-k-n_0]\rightarrow sys...)
(No difference)

Revision as of 19:30, 11 September 2008

part a

it can't be a time invariant because output is not same.

$ X_k[n] = \delta[n-k] $

$ \delta[n-k]\rightarrow time delay\rightarrow\delta[n-k-n_0]\rightarrow system \rightarrow (k+n_0+1)^2\delta[n-(k+n_0+1)] $

$ \delta[n-k]\rightarrow system \rightarrow Y_k[n] \rightarrow $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood