(New page: ==Periodic signal revisited== 1. I am considering my example x=cos2t from 0 to 5pi used in the previous homework part 1.E. It is continuous signal if sampled at 0.01 but converting it to ...)
 
 
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==Periodic signal revisited==
 
==Periodic signal revisited==
1. I am considering my example x=cos2t from 0 to 5pi used in the previous homework part 1.E. It is continuous signal if sampled at 0.01
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1. I am considering my example x=cos2t from 0 to 5pi used in the previous homework part 1.E.
  
but converting it to DT and increasing the sampling rate shows a non-periodic set of points
+
[[Image:ct_ECE301Fall2008mboutin.jpg]]
 +
 
 +
sampled at 0.01
 +
 
 +
[[Image:dt0_ECE301Fall2008mboutin.jpg]]
 +
 
 +
but converting it to DT and increasing the sampling rate to 0.08 shows a non-periodic set of points
 +
 
 +
[[Image:untitled12_ECE301Fall2008mboutin.jpg]]
 +
 
 +
2. for making a periodic siganl
 +
lets take an example of <math>X=\ e^t</math>
 +
 
 +
the graph of the function is
 +
 
 +
[[Image:nonperiodic12_ECE301Fall2008mboutin.jpg]]
 +
 
 +
to convert it to periodic we use the following matlabcode
 +
<pre>
 +
%referred the code of paul sceffler
 +
clc
 +
clear
 +
 
 +
t=.01:.01:1;
 +
x=exp(t);
 +
i=[];
 +
for d=1:5
 +
    i=[i,x];
 +
end
 +
 
 +
t=[.01:.01:5];
 +
plot(t,i)
 +
</pre>
 +
 
 +
the periodic function thus is
 +
 
 +
[[Image:periodic12_ECE301Fall2008mboutin.jpg]]

Latest revision as of 19:18, 11 September 2008

Periodic signal revisited

1. I am considering my example x=cos2t from 0 to 5pi used in the previous homework part 1.E.

Ct ECE301Fall2008mboutin.jpg

sampled at 0.01

Dt0 ECE301Fall2008mboutin.jpg

but converting it to DT and increasing the sampling rate to 0.08 shows a non-periodic set of points

Untitled12 ECE301Fall2008mboutin.jpg

2. for making a periodic siganl lets take an example of $ X=\ e^t $

the graph of the function is

Nonperiodic12 ECE301Fall2008mboutin.jpg

to convert it to periodic we use the following matlabcode

%referred the code of paul sceffler
clc
clear

t=.01:.01:1;
x=exp(t);
i=[];
for d=1:5
    i=[i,x];
end

t=[.01:.01:5];
plot(t,i)

the periodic function thus is

Periodic12 ECE301Fall2008mboutin.jpg

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