SVM Old Kiwi.jpg

We have 3 points. The labels are shown in the figure.


Writing the Equation for the dual problem: SVM1 Old Kiwi.jpg


$ Q(\alpha )= {\alpha }_{1}+{\alpha }_{2}+{\alpha }_{3}-[0.5{{\alpha }_{1}}^{2}+0.5{{\alpha }_{2}}^{2}+2{{\alpha }_{3}}^{2}+2{\alpha }_{2}{\alpha }_{3}] $


Subject to constraints

$ -{\alpha }_{1}+{\alpha }_{2}+{\alpha }_{3}=0 $

and $ {\alpha }_{1}\geq 0; {\alpha }_{2}\geq 0;{\alpha }_{3}\geq 0 $ Differentiating partially with respect to $ {\alpha }_{1},{\alpha }_{2}, {\alpha }_{3} $

$ 1-{\alpha }_{1}=0 $

$ 1-{\alpha }_{2}-2{\alpha }_{3}=0 $ $ 1-2{\alpha }_{2}-4{\alpha }_{3}=0 $

We always use the constraint equation, and then use 2 of these three equations. On solving, we get

$ {\alpha }_{1} = 1 $ $ {\alpha }_{2} = 1 $ $ {\alpha }_{3} = 0 $


SVM2 Old Kiwi.jpg

b=0

Thus, we get a line through the origin with slope 1. This is the same boundary as was expected.

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang