Grading format:

Similar to the grading format of HW1, HW2 is graded for completeness as well as theoretical understanding of course material.

Correction to original solution Q3:

The graph for x[n-k] should be 0 at n, and 1's from n+1 to n+10

The correct solution (as Kim described) is as follows:

y[n]=0 for n<-10

y[n]=n+11 for -10<=n<=-1

y[n]=9-n for 0<=n<=8

y[n]=0 for n>8

Comments:

- In Q2, $ (-1)^n = e^{j\pi n} $.

- When computing the DTFT using the summation formula, note that some expressions are in the form of geometric series.

- In Q3, convolution must be separated into various cases. The analytical expression will vary depending on the case. Also, drawing the signals is very helpful.