## Example of Computation of inverse Fourier transform (CT signals)

Let the signal $X(\omega)$ be equal to:

$X(\omega) = \delta(\omega) + \delta(\omega - 2) - \delta(\omega - 3) \,$

The Inverse Fourier Transform of a signal in Continuous Time is:

$x(t)=\frac{1}{2\pi}\int_{-\infty}^{\infty}X(\omega)e^{j\omega t}d\omega \,$

Using this, we obtain:

$x(t)=\frac{1}{2\pi}\int_{-\infty}^{\infty}(\delta(\omega)e^{j\omega t} + \delta(\omega - 2)e^{j\omega t} - \delta(\omega - 3)e^{j\omega t}) d\omega \,$

$x(t) = \frac{1}{2\pi}(e^{j\omega t} +e^{j2\omega t} - e^{j3\omega t}) \,$