Example of Computation of inverse Fourier transform (CT signals)

A practice problem on CT Fourier transform



Let the signal $ X(\omega) $ be equal to:

$ X(\omega) = \delta(\omega) + \delta(\omega - 2) - \delta(\omega - 3) \, $


The Inverse Fourier Transform of a signal in Continuous Time is:

$ x(t)=\frac{1}{2\pi}\int_{-\infty}^{\infty}X(\omega)e^{j\omega t}d\omega \, $


Using this, we obtain:

$ x(t)=\frac{1}{2\pi}\int_{-\infty}^{\infty}(\delta(\omega)e^{j\omega t} + \delta(\omega - 2)e^{j\omega t} - \delta(\omega - 3)e^{j\omega t}) d\omega \, $

$ x(t) = \frac{1}{2\pi}(e^{j\omega t} +e^{j2\omega t} - e^{j3\omega t}) \, $


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Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood