Question

Supposing we are given a signal $ x(t) $

1) $ x(t) $ is real and odd

2) $ x(t) $ is periodic with period $ T = 5 $

3) $ a_{0}=0 $

4) peak to peak value of 3


Specify a signal that satisfies the given conditions.

Answer

$ signal=\frac{3}{2}sin(\frac{2\pi}{5}t) $

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