Periodic DT Signal

$ x[n]=-\frac{1}{2}cos(3\pi n)+sin(3\pi n)\! $.


Fourier Series Coefficients

$ x[n]=-\frac{1}{2}[\frac{e^{j3\pi n}+e^{-j3\pi n}}{2}]+\frac{e^{j3\pi n}-e^{-3\pi n}}{j2} $


$ x[n]=-\frac{1}{4}e^{j3\pi n}-\frac{1}{4}e^{-j3\pi n}+\frac{1}{j2}e^{3\pi n}-\frac{1}{j2}e^{-j3\pi n} $

$ a_{-1} = -\frac{1}{4}-j\frac{1}{2} $

$ a_{0} = 0\! $

$ a_{1} = -\frac{1}{4}+j\frac{1}{2} $

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang