$ \,cos(2t) $ can be written as $ \ {e^{-2jt} + e^{2jt} \over 2} $ based on Euler's forumla:

$ \cos x = \mathrm{Re}\{e^{ix}\} ={e^{ix} + e^{-ix} \over 2} $

Since the system is linear, and one of the properties of linear system is that:


Input $ \,ax_1(t)+bx_2(t) $ equals to the output $ \, ay_1(t)+by_2(t) $


and


$ \frac{e^{2t}}{2} \to t\cdot\frac{e^{-2t}}{2} $ and $ \frac{e^{-2t}}{2} \to t\cdot\frac{e^{2t}}{2} $


$ t\cdot\frac{e^{-2jt}}{2} + t\cdot\frac{e^{2jt}}{2} $


$ t\cdot\frac{e^{-2jt}+e^{2jt}}{2} $


$ \therefore \ t \cdot cos(2t) $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood