E-a

No,the system can not be time-invariant.

Based on the data, if X has been delayed by 1, Y is not only delayed by 1,but also scale in the magnitude.

Since if we operate delay, the outputs won't match, the system is not time-invariant.

E-b

Since the system is linear, the input should be X[n] = u[n] in order to get Y[n]=u[n-1], where k=0

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang