Energy of 2cos(t)

E = $ \int_{0}^{2\pi} \vert 2cos(t) \vert^2 \ , dx $


 = 	$  4/2  \int_{0}^{2\pi} (1 + 2cos(t)) \ , dx $
 =    2(t + sin(2t))
 =    $ 2\pi $


Power of 2cos(t)

P = $ 1/2\pi \int_{0}^{2\pi} \vert 2cos(t) \vert^2 \ , dx $

 =     $  4/4\pi  \int_{0}^{2\pi} (1 + 2cos(t)) \ , dx $
 =     $  1/\pi(2\pi + 0) $
 =      2

Alumni Liaison

BSEE 2004, current Ph.D. student researching signal and image processing.

Landis Huffman