ENERGY

The energy of a signal can by computed by the following Energy formula:

$ E = \int_{t_1}^{t_2} y(t)\, dt $

on the other hand, power of a signal can be calculated by:


$ P = \frac{1}{t_2 - t_1} \int_{t_1}^{t_2} y(t)\, dt $

Let's now calculate the energy and power of the following signal: $ y(t) = x^{2} $ for $ t_1 = 0 $ and $ t_2 = 5 $

$ E = \int_{0}^{5} x^{2}\, dt = \frac{1}{3} \left [ x^{3} \right ] _0^5 = \frac{125}{3} $


$ P = \frac{1}{5 - 0} \int_{0}^{5} x^{2}\, dt = \frac{25}{3} $

Alumni Liaison

Have a piece of advice for Purdue students? Share it through Rhea!

Alumni Liaison