According to the following equations :

$ exp(2jt)=t* exp(-2jt) $

and

$ exp(-2jt)=t * exp(2jt) $

we see that the system equation is:

$ x(-t)->t*x(t) $

in case of cosine function
$ cos(t)->t*cos(t) $

$ cos(-t)->*cos(-t) $ thus $ cos(-t)=t*cos(t) $hence it is an even function

Alumni Liaison

Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett