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===Answer 1===
 
===Answer 1===
 
First off u[n] is nonzero for any value of n >= 0. The delta function is nonzero only for when n-k=0 or n=k. Since n must be >=0 then the values of k must conform to 0=<k<=15. This makes the function behave like u[n]-u[n-15]. I am not sure if this is completely correct.  
 
First off u[n] is nonzero for any value of n >= 0. The delta function is nonzero only for when n-k=0 or n=k. Since n must be >=0 then the values of k must conform to 0=<k<=15. This makes the function behave like u[n]-u[n-15]. I am not sure if this is completely correct.  
:Instructor's comments. Pretty good! You've got all the elements of the correct justification! Now can you write a justification "in maths" instead of "in words"? -pm
+
:<span style="color:blue"> Instructor's comments. Pretty good! You've got all the elements of the correct justification! Now can you write a justification "in maths" instead of "in words"? -pm </span>
:<span style="color:green"> TA's comments. Using distributive property. the equation can be rewritten as <math>\sum_{k=-7}^{15}  u[n]\delta [n-k].</math>
+
 
 +
:<span style="color:green"> TA's comments. Using distributive property. the equation can be rewritten as </span>
 +
::<math>\sum_{k=-7}^{15}  u[n]\delta [n-k].</math>
 
===Answer 2===
 
===Answer 2===
 
Write it here.
 
Write it here.

Revision as of 06:39, 29 August 2011

Simplify this summation

$ u[n] \sum_{k=-7}^{15}  \delta [n-k].  $

(Justify your answer.)


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Answer 1

First off u[n] is nonzero for any value of n >= 0. The delta function is nonzero only for when n-k=0 or n=k. Since n must be >=0 then the values of k must conform to 0=<k<=15. This makes the function behave like u[n]-u[n-15]. I am not sure if this is completely correct.

Instructor's comments. Pretty good! You've got all the elements of the correct justification! Now can you write a justification "in maths" instead of "in words"? -pm
TA's comments. Using distributive property. the equation can be rewritten as
$ \sum_{k=-7}^{15} u[n]\delta [n-k]. $

Answer 2

Write it here.

Answer 3

write it here.


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Ryne Rayburn