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         = e^{j\pi t} </math>
 
         = e^{j\pi t} </math>
  
using the fact that <math>\delta (t-x)f(t) = \delta (t-x)f(x)</math>
+
using the fact that <math>\delta (t-T)f(t) = \delta (t-T)f(T)</math>
 
===Answer 2===
 
===Answer 2===
 
Write it here.
 
Write it here.

Revision as of 16:59, 3 September 2011

Continuous-time Fourier transform of a complex exponential

What is the Fourier transform of $ x(t)= e^{j \pi t} $? Justify your answer.


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Answer 1

Guess: $ X(f)=\delta (f-\frac{1}{2}) $

Proof:

$ x(t)=\int_{-\infty}^{\infty} X(f)e^{j2\pi ft} df = \int_{-\infty}^{\infty} \delta (f-\frac{1}{2})e^{j2\pi ft} df = \int_{-\infty}^{\infty} \delta (f-\frac{1}{2})e^{j\pi t} df = e^{j\pi t} \int_{-\infty}^{\infty} \delta (f-\frac{1}{2}) df = e^{j\pi t} $

using the fact that $ \delta (t-T)f(t) = \delta (t-T)f(T) $

Answer 2

Write it here.

Answer 3

write it here.


Back to ECE438 Fall 2011 Prof. Boutin

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