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         = e^{j\pi t} </math>
 
         = e^{j\pi t} </math>
  
 +
using the fact that <math>\delta (t-x)f(t) = \delta (t-x)f(x)</math>
 
===Answer 2===
 
===Answer 2===
 
Write it here.
 
Write it here.

Revision as of 16:58, 3 September 2011

Continuous-time Fourier transform of a complex exponential

What is the Fourier transform of $ x(t)= e^{j \pi t} $? Justify your answer.


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Answer 1

Guess: $ X(f)=\delta (f-\frac{1}{2}) $

Proof:

$ x(t)=\int_{-\infty}^{\infty} X(f)e^{j2\pi ft} df = \int_{-\infty}^{\infty} \delta (f-\frac{1}{2})e^{j2\pi ft} df = \int_{-\infty}^{\infty} \delta (f-\frac{1}{2})e^{j\pi t} df = e^{j\pi t} \int_{-\infty}^{\infty} \delta (f-\frac{1}{2}) df = e^{j\pi t} $

using the fact that $ \delta (t-x)f(t) = \delta (t-x)f(x) $

Answer 2

Write it here.

Answer 3

write it here.


Back to ECE438 Fall 2011 Prof. Boutin

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang