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2. '''z''' = (z1,z2) = '''v''' + '''w''' = (v1+w1, v2+w2)
 
2. '''z''' = (z1,z2) = '''v''' + '''w''' = (v1+w1, v2+w2)
  
So, |z1| = |v1 + w1| () |v1| + |w1| < v2 + w2 = z2
+
So, |z1| = |v1 + w1| &le; |v1| + |w1| < v2 + w2 = z2
  
 
3. What it means for '''z''' to be in V: |z1| < z2
 
3. What it means for '''z''' to be in V: |z1| < z2

Revision as of 08:42, 25 November 2012

SUBSPACE

To be a subspace of vectors the following must be true:

1. One set must be a subset of another set

2. The set must be closed under scalar multiplication

3. The set must be closed under vector addition


Proving one set is a subset of another set

Given sets A and B we say that is is a subset of B if every element of A is also an element of B, that is,

x∈A implies x∈B


Basic Outline of the Proof that A is a subset of B:


· Suppose x ∈ A

1. Say what it means for x to be in A

2. Mathematical details

3. Conclude that x satisfies what it means to be in B


· Conclude x∈B


Example

Let A be the set of scalars divisible by 6 and let B be the even numbers. Prove that A is a subset of B.


· Suppose x ∈ A:

1. What it means for x to be in A: x = 6k for any scalar k

2. x = 2 × (3k)

  3k = C

3. What it means for x to be in B: x = 2C


· Conclude x∈B


Closed Under Scalar Multiplication

A set of vectors is closed under scalar multiplication if for every v∈V and every c∈\mathbb{R} we have cv∈V


Basic Outline of the Proof V is Closed Under Scalar Multiplication:



· Suppose v∈V and c∈\mathbb{R}

1. Say what it means for v to be in V

2. Mathematical details

3. Conclude that cv satisfies what it means to be in V


· Conclude cv∈V


Closed Under Vector Addition

A set of vectors is closed under vector addition if for every v and w ∈ V we have v + w ∈ V


Basic Outline of the Proof V is Closed Under Vector Addition:


· Suppose v and w ∈ V

1. Say what it means for v and w to be in V

2. Mathematical details

3. Conclude that v+ w satisfies what it means to be in V


· Conclude v + w ∈ V


Example

Let V be the set of points above the graph of the absolute value function

· Suppose v and w ∈ V

1. What it means for v and w to be in V :

v = (v1, v2) and v2 > |v1|

w = (w1, w2) and w2 > |w1|

2. z = (z1,z2) = v + w = (v1+w1, v2+w2)

So, |z1| = |v1 + w1| ≤ |v1| + |w1| < v2 + w2 = z2

3. What it means for z to be in V: |z1| < z2


· Conclude z = v + w ∈ V

Alumni Liaison

Prof. Math. Ohio State and Associate Dean
Outstanding Alumnus Purdue Math 2008

Jeff McNeal