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<b> Convolution of Unit Step Function: </b> | <b> Convolution of Unit Step Function: </b> | ||

− | To take a convolution, first determine whether the system is CT or DT and use the correct formula. Next it's time to simplify. Originally the bounds are set to negative and positive infinity. The unit step function will determine the new set of bounds. Consider the following unit step function as an example: <math> u(2t-1)\ </math>. This function will be a zero as long as <math> (2t-1) </math> is less than 0. Solve for t and apply the new bounds. Next its time for the real work! | + | : To take a convolution, first determine whether the system is CT or DT and use the correct formula. Next it's time to simplify. Originally the bounds are set to negative and positive infinity. The unit step function will determine the new set of bounds. Consider the following unit step function as an example: <math> u(2t-1)\ </math>. This function will be a zero as long as <math> (2t-1) </math> is less than 0. Solve for t and apply the new bounds. Next its time for the real work! |

<b> Convolution of Delta Function: </b> | <b> Convolution of Delta Function: </b> | ||

− | Consider <math> \delta (ax+b) </math>. Simplify this convolution by solving for when the delta function is set to one. (This is when the <math> (ax+b)\ </math> is equal to zero). That is the only value of the integration or sum, so replace t accordingly and solve. | + | : Consider <math> \delta (ax+b) </math>. Simplify this convolution by solving for when the delta function is set to one. (This is when the <math> (ax+b)\ </math> is equal to zero). That is the only value of the integration or sum, so replace t accordingly and solve. |

## Latest revision as of 11:54, 8 December 2008

** Convolution of Unit Step Function: **

- To take a convolution, first determine whether the system is CT or DT and use the correct formula. Next it's time to simplify. Originally the bounds are set to negative and positive infinity. The unit step function will determine the new set of bounds. Consider the following unit step function as an example: $ u(2t-1)\ $. This function will be a zero as long as $ (2t-1) $ is less than 0. Solve for t and apply the new bounds. Next its time for the real work!

** Convolution of Delta Function: **

- Consider $ \delta (ax+b) $. Simplify this convolution by solving for when the delta function is set to one. (This is when the $ (ax+b)\ $ is equal to zero). That is the only value of the integration or sum, so replace t accordingly and solve.