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[[Category: asan]]
 
[[Category: asan]]
 
[[Category: Bonus]]
 
[[Category: Bonus]]
Given:
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Given: <math>y[n]=x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k])</math>
 
+
<math>y[n]=x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k])</math>
+
  
 
#<math> x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k])</math>
 
#<math> x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k])</math>

Revision as of 07:40, 25 November 2008

Given: $ y[n]=x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k]) $

  1. $ x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k]) $
  2. $ k'=n-k $
  3. $ x[n]*h[n]=\sum_{k'=\infty}^{-\infty}(x[n-k']h[k']) $ from 1 and 2
  4. $ x[n]*h[n]=h[n]*x[n] $

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Questions/answers with a recent ECE grad

Ryne Rayburn