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[[Category:ECE201]]
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[[Category:ECE]]
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[[Category:ECE201Spring2015Peleato]]
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[[Category:circuits]]
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[[Category:linear circuits]]
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[[Category:problem solving]]
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=Template for Text practice problem ''(erase this line)''=
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<center><font size= 4>
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'''Practice question for [[ECE201]]: "Linear circuit analysis I" '''
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By: [[ECE]] student Karthik Bokka
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Topic: Combining resistors
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</center>
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==Question==
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[[File:IMAG0326.jpg|thumbnail]]
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===Answer ===
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Since the switch is not connected the two 2 ohm resistors on the left are in series, which makes that 4 ohms, and the 4 ohm and 5 ohm resistor on the right are in series as well so that becomes 9 ohms. After that there will be a 4 ohm resistor on the left of the switch and a 9 ohm resistor on the right. These two resistors are in parallel so the equivalent resistance is 36/13 ohms.
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==Questions and comments==
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If you have any questions, comments, etc. please post them below
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*Comment 1
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**Answer to Comment 1
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*Comment 2
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**Answer to Comment 2
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[[2015 Spring ECE 201 Peleato|Back to 2015 Spring ECE 201 Peleato]]
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[[ECE201|Back to ECE201]]
  
  

Latest revision as of 01:43, 7 May 2015


Combining Resistors

Template for Text practice problem (erase this line)

Practice question for ECE201: "Linear circuit analysis I"

By: ECE student Karthik Bokka

Topic: Combining resistors


Question

IMAG0326.jpg


Answer

Since the switch is not connected the two 2 ohm resistors on the left are in series, which makes that 4 ohms, and the 4 ohm and 5 ohm resistor on the right are in series as well so that becomes 9 ohms. After that there will be a 4 ohm resistor on the left of the switch and a 9 ohm resistor on the right. These two resistors are in parallel so the equivalent resistance is 36/13 ohms.


Questions and comments

If you have any questions, comments, etc. please post them below

  • Comment 1
    • Answer to Comment 1
  • Comment 2
    • Answer to Comment 2

Back to 2015 Spring ECE 201 Peleato

Back to ECE201



Back to 2015 Spring ECE 201 Peleato

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