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Well the probability of 3 is twice as likely.  So we set up an equation that is equal to 1 because that is the probability of any answer.  So, 2x +5x = 1 is the equation.  So solver for a and you get 1/7 probability of rolling 1,2,4,5,6 and since 3 is twice as likely you get 2*1/7  which equals 2/7
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Well the probability of 3 is twice as likely.  So we set up an equation that is equal to 1 because that is the probability of any answer.  So, 2x +5x = 1 is the equation.  So solve for a and you get 1/7 probability of rolling 1,2,4,5,6 and since 3 is twice as likely you get 2*1/7  which equals 2/7

Revision as of 09:55, 4 March 2009

What is the probability of each outcome when a loaded die is rolled, if 3 is twice as likely to appear as each of the other five numbers on the die

Well the probability of 3 is twice as likely. So we set up an equation that is equal to 1 because that is the probability of any answer. So, 2x +5x = 1 is the equation. So solve for a and you get 1/7 probability of rolling 1,2,4,5,6 and since 3 is twice as likely you get 2*1/7 which equals 2/7

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Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood