Line 31: Line 31:
  
 
<math>\begin{align}
 
<math>\begin{align}
     Vout = (\frac{-R_f}{R_1})V_1 + (\frac{-R_f}{R_1})V_2\\
+
     Vout = (\frac{-R_f}{R_1})Vin\\
 +
By using the superposition principle we can look at one voltage source at a time, then add them together to find Vout.
 
     Vout = (\frac{-72}{24})4 + (\frac{-72}{36})6\\
 
     Vout = (\frac{-72}{24})4 + (\frac{-72}{36})6\\
 
     Vout = -24V
 
     Vout = -24V

Revision as of 18:12, 26 April 2015


Summing Amplifier Practice

Practice question for ECE201: "Linear circuit analysis I"

By: Chinar Dhamija

Topic: Summing Op Amp


Question

Find the output voltage, Vout.

ECE201 P4.png


Answer

First we know that $ V_- $ = $ V_+ $
$ V_- $ = 0V = $ V_+ $
The op amp can be ignored for this particular problem.
We can apply the formula we learned in class to solve for Vout.

$ \begin{align} Vout = (\frac{-R_f}{R_1})Vin\\ By using the superposition principle we can look at one voltage source at a time, then add them together to find Vout. Vout = (\frac{-72}{24})4 + (\frac{-72}{36})6\\ Vout = -24V \end{align} $


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