| Line 31: | Line 31: | ||
<math>\begin{align} | <math>\begin{align} | ||
| − | Vout = (\frac{-R_f}{R_1})V_1 + (\frac{-R_f}{R_1})V_2 | + | Vout = (\frac{-R_f}{R_1})V_1 + (\frac{-R_f}{R_1})V_2\\ |
| − | Vout = (\frac{-72}{24})4 + (\frac{-72}{36})6 | + | Vout = (\frac{-72}{24})4 + (\frac{-72}{36})6\\ |
Vout = -24V | Vout = -24V | ||
\end{align} | \end{align} | ||
Revision as of 17:57, 26 April 2015
Summing Amplifier Practice
Practice question for ECE201: "Linear circuit analysis I"
By: Chinar Dhamija
Topic: Summing Op Amp
Question
Find the output voltage, Vout.
Answer
First we know that $ V_- $ = $ V_+ $
$ V_- $ = 0V = $ V_+ $
The op amp can be ignored for this particular problem.
We can apply the formula we learned in class to solve for Vout.
$ \begin{align} Vout = (\frac{-R_f}{R_1})V_1 + (\frac{-R_f}{R_1})V_2\\ Vout = (\frac{-72}{24})4 + (\frac{-72}{36})6\\ Vout = -24V \end{align} $
Questions and comments
If you have any questions, comments, etc. please post them below
- Comment 1
- Answer to Comment 1
- Comment 2
- Answer to Comment 2
