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Find the value of Vout.
 
Find the value of Vout.
  
[[File:ECE201_P2.jpeg|500px|center]]
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[[File:ECE201_P2.jpg|500px|center]]
  
 
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<math> V_+ = 6 = V_- </math><br />
 
<math> V_+ = 6 = V_- </math><br />
  
Now that we know the voltage at the <math> V_- </math> node we can find Vout by using the following equation.
+
Now that we know the voltage at the <math> V_- </math> node we can find Vout by using the following equation.<br />
 
<math>\begin{align}
 
<math>\begin{align}
 
i = \frac{V_- - Vout}{8}\\
 
i = \frac{V_- - Vout}{8}\\

Latest revision as of 15:56, 2 May 2015


Op Amp Practice with Voltage Division

Practice question for ECE201: "Linear circuit analysis I"

By: Chinar Dhamija

Topic: Op Amp


Question

Find the value of Vout.

ECE201 P2.jpg


Answer

The first step would be to solve for i using Ohm's Law.
$ i = \frac{12}{4} $
$ i = 3A $

We know that $ V_+ = V_- $.
In order to find $ V_+ $ we need to use voltage division at the node connecting the 2 and 4 ohm resistor.
$ V_+ = \frac{4}{4 + 2} * 9 $
$ V_+ = 6 = V_- $

Now that we know the voltage at the $ V_- $ node we can find Vout by using the following equation.
$ \begin{align} i = \frac{V_- - Vout}{8}\\ 3 = \frac{6 - Vout}{8}\\ 24 = 6 - Vout\\ Vout = -18 V\\ \end{align} $


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