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Find the value of Vout. | Find the value of Vout. | ||
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===Answer === | ===Answer === | ||
| − | + | The first step would be to solve for i using Ohm's Law.<br /> | |
| − | <math> | + | <math> i = \frac{12}{4} </math><br /> |
| + | <math> i = 3A </math><br /> | ||
| − | + | We know that <math>V_+ = V_- </math>.<br /> | |
| − | + | In order to find <math> V_+ </math> we need to use voltage division at the node connecting the 2 and 4 ohm resistor.<br /> | |
| − | <math> | + | <math> V_+ = \frac{4}{4 + 2} * 9 </math><br /> |
| − | + | <math> V_+ = 6 = V_- </math><br /> | |
| − | <math> | + | |
| − | + | ||
| − | <math> | + | |
| − | + | Now that we know the voltage at the <math> V_- </math> node we can find Vout by using the following equation.<br /> | |
<math>\begin{align} | <math>\begin{align} | ||
| − | + | i = \frac{V_- - Vout}{8}\\ | |
| − | + | 3 = \frac{6 - Vout}{8}\\ | |
| − | + | 24 = 6 - Vout\\ | |
| − | + | Vout = -18 V\\ | |
\end{align} | \end{align} | ||
</math> | </math> | ||
Latest revision as of 15:56, 2 May 2015
Contents
Op Amp Practice with Voltage Division
Practice question for ECE201: "Linear circuit analysis I"
By: Chinar Dhamija
Topic: Op Amp
Question
Find the value of Vout.
Answer
The first step would be to solve for i using Ohm's Law.
$ i = \frac{12}{4} $
$ i = 3A $
We know that $ V_+ = V_- $.
In order to find $ V_+ $ we need to use voltage division at the node connecting the 2 and 4 ohm resistor.
$ V_+ = \frac{4}{4 + 2} * 9 $
$ V_+ = 6 = V_- $
Now that we know the voltage at the $ V_- $ node we can find Vout by using the following equation.
$ \begin{align} i = \frac{V_- - Vout}{8}\\ 3 = \frac{6 - Vout}{8}\\ 24 = 6 - Vout\\ Vout = -18 V\\ \end{align} $
Questions and comments
If you have any questions, comments, etc. please post them below
- Comment 1
- Answer to Comment 1
- Comment 2
- Answer to Comment 2
