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| − | [[Category: | + | <br /> |
| + | [[Category:ECE201]] | ||
| + | [[Category:ECE]] | ||
| + | [[Category:ECE201Spring2015Peleato]] | ||
| + | [[Category:circuits]] | ||
| + | [[Category:linear circuits]] | ||
| + | [[Category:problem solving]] | ||
| − | = | + | =Op Amp Practice with Voltage Division= |
| + | <center><font size= 4> | ||
| + | '''Practice question for [[ECE201]]: "Linear circuit analysis I" ''' | ||
| + | </font size> | ||
| + | By: Chinar Dhamija | ||
| + | Topic: Op Amp | ||
| − | + | </center> | |
| + | ---- | ||
| + | ==Question== | ||
| + | Find the value of Vout. | ||
| + | [[File:ECE201_P2.jpg|500px|center]] | ||
| + | ---- | ||
| + | ---- | ||
| + | ===Answer === | ||
| + | The first step would be to solve for i using Ohm's Law.<br /> | ||
| + | <math> i = \frac{12}{4} </math><br /> | ||
| + | <math> i = 3A </math><br /> | ||
| + | We know that <math>V_+ = V_- </math>.<br /> | ||
| + | In order to find <math> V_+ </math> we need to use voltage division at the node connecting the 2 and 4 ohm resistor.<br /> | ||
| + | <math> V_+ = \frac{4}{4 + 2} * 9 </math><br /> | ||
| + | <math> V_+ = 6 = V_- </math><br /> | ||
| − | [[ 2015 Spring ECE 201 Peleato|Back to 2015 Spring ECE 201 Peleato]] | + | Now that we know the voltage at the <math> V_- </math> node we can find Vout by using the following equation.<br /> |
| + | <math>\begin{align} | ||
| + | i = \frac{V_- - Vout}{8}\\ | ||
| + | 3 = \frac{6 - Vout}{8}\\ | ||
| + | 24 = 6 - Vout\\ | ||
| + | Vout = -18 V\\ | ||
| + | \end{align} | ||
| + | </math> | ||
| + | |||
| + | ---- | ||
| + | ==Questions and comments== | ||
| + | If you have any questions, comments, etc. please post them below | ||
| + | *Comment 1 | ||
| + | **Answer to Comment 1 | ||
| + | *Comment 2 | ||
| + | **Answer to Comment 2 | ||
| + | ---- | ||
| + | [[2015 Spring ECE 201 Peleato|Back to 2015 Spring ECE 201 Peleato]] | ||
| + | |||
| + | [[ECE201|Back to ECE201]] | ||
Latest revision as of 15:56, 2 May 2015
Contents
Op Amp Practice with Voltage Division
Practice question for ECE201: "Linear circuit analysis I"
By: Chinar Dhamija
Topic: Op Amp
Question
Find the value of Vout.
Answer
The first step would be to solve for i using Ohm's Law.
$ i = \frac{12}{4} $
$ i = 3A $
We know that $ V_+ = V_- $.
In order to find $ V_+ $ we need to use voltage division at the node connecting the 2 and 4 ohm resistor.
$ V_+ = \frac{4}{4 + 2} * 9 $
$ V_+ = 6 = V_- $
Now that we know the voltage at the $ V_- $ node we can find Vout by using the following equation.
$ \begin{align} i = \frac{V_- - Vout}{8}\\ 3 = \frac{6 - Vout}{8}\\ 24 = 6 - Vout\\ Vout = -18 V\\ \end{align} $
Questions and comments
If you have any questions, comments, etc. please post them below
- Comment 1
- Answer to Comment 1
- Comment 2
- Answer to Comment 2
