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Find the value of Vout. | Find the value of Vout. | ||
| − | [[File:ECE201_P4_1. | + | [[File:ECE201_P4_1.jpeg|400px|center]] |
| − | [[File:ECE201_P4_2.png| | + | [[File:ECE201_P4_2.png|20px|center]] |
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<math> a = 4 </math> and <math> b = -6 </math><br /> | <math> a = 4 </math> and <math> b = -6 </math><br /> | ||
| − | Since we have both a and b values you can plug that into the Vs' equation and solve for Vs'. | + | Since we have both a and b values you can plug that into the Vs' equation and solve for Vs'.<br /> |
<math>\begin{align} | <math>\begin{align} | ||
20 = Vs'a + 4b\\ | 20 = Vs'a + 4b\\ | ||
Revision as of 15:30, 2 May 2015
Contents
Op Amp Practice with Voltage Division
Practice question for ECE201: "Linear circuit analysis I"
By: Chinar Dhamija
Topic: Op Amp
Question
Find the value of Vout.
Answer
In order to find Vs' we have the following equation:
$ 20 = Vs'a + 4b $
From the information present in the table two systems of equations can be created to solve for a and b.
First equation:
$ 10 = 4a + b $
Second equation:
$ 40 = 10a + 0b $
After solving the above system of equations you get:
$ a = 4 $ and $ b = -6 $
Since we have both a and b values you can plug that into the Vs' equation and solve for Vs'.
$ \begin{align} 20 = Vs'a + 4b\\ 20 = Vs'(4) + 4(-6)\\ 44 = 4Vs'\\ Vs' = 11 V \end{align} $
Questions and comments
If you have any questions, comments, etc. please post them below
- Comment 1
- Answer to Comment 1
- Comment 2
- Answer to Comment 2
