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     \frac{V_+ - 0}{11} + \frac{V_+ - Vout}{44} = & 0\\
 
     \frac{V_+ - 0}{11} + \frac{V_+ - Vout}{44} = & 0\\
 
     \frac{20}{11} + \frac{20 - Vout}{44} = & 0\\
 
     \frac{20}{11} + \frac{20 - Vout}{44} = & 0\\
     80 + 20 - Vout = 0
+
     80 + 20 - Vout = &0\\
 
     Vout = 100V
 
     Vout = 100V
 
\end{align}
 
\end{align}

Latest revision as of 17:45, 26 April 2015


Op Amp Practice

Practice question for ECE201: "Linear circuit analysis I"

By: Chinar Dhamija

Topic: Op Amp


Question

Find the output voltage, Vout.

ECE201 P3.png


Answer

First we know that $ V_- $ = $ V_+ $
$ V_- $ = 20V = $ V_+ $ The next step would be to do nodal analysis at the node where the two resistor wires intersect.
Let's call that node V+:
$ \begin{align} \frac{V_+ - 0}{11} + \frac{V_+ - Vout}{44} = & 0\\ \frac{20}{11} + \frac{20 - Vout}{44} = & 0\\ 80 + 20 - Vout = &0\\ Vout = 100V \end{align} $


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