Line 23: Line 23:
 
&= \frac{\mu_0}{2 \pi a \cdot b}\\
 
&= \frac{\mu_0}{2 \pi a \cdot b}\\
 
& = \int_a^{-\infty} jzdhfbvzjhvz dt \\
 
& = \int_a^{-\infty} jzdhfbvzjhvz dt \\
& = \sum_{k=0}^{-\infty} kzdjfgdzjkfg
+
& = \sum_{k=0}^{-\infty} kzdjfgdzjkfg \\
& x(t) = sin(6 \pi t), \omega_{o} = 6\pi
+
& x(t) = sin(6 \pi t), \omega_{o} = 6\pi \\
& x(t) = 2 + cos(6 \pi t) - \frac{1}{2} sin(3 \pi t), \omega_{o} = 3\pi
+
& x(t) = 2 + cos(6 \pi t) - \frac{1}{2} sin(3 \pi t), \omega_{o} = 3\pi \\
  
 
\end{align}
 
\end{align}

Revision as of 20:38, 25 April 2019


Fourier Series Coefficients

A project by Kalyan Mada



Introduction

I am going to compute some fourier series coefficients.


CT signals

$ \begin{align} \bar f(x) &= \oint_S g(x) dx \\ &= \int_a^b g(x) dx \\ &= \frac{\mu_0}{2 \pi a \cdot b}\\ & = \int_a^{-\infty} jzdhfbvzjhvz dt \\ & = \sum_{k=0}^{-\infty} kzdjfgdzjkfg \\ & x(t) = sin(6 \pi t), \omega_{o} = 6\pi \\ & x(t) = 2 + cos(6 \pi t) - \frac{1}{2} sin(3 \pi t), \omega_{o} = 3\pi \\ \end{align} $


DT signals



Questions and comments

If you have any questions, comments, etc. please post them here.


[to 2019 Spring ECE 301 Boutin]


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