## Contents

# Op Amp Practice with Voltage Division

**Practice question for ECE201: "Linear circuit analysis I" **

By: Chinar Dhamija

Topic: Op Amp

## Question

Find the value of Vout.

### Answer

The first step would be to solve for i using Ohm's Law.

$ i = \frac{12}{4} $

$ i = 3A $

We know that $ V_+ = V_- $.

In order to find $ V_+ $ we need to use voltage division at the node connecting the 2 and 4 ohm resistor.

$ V_+ = \frac{4}{4 + 2} * 9 $

$ V_+ = 6 = V_- $

Now that we know the voltage at the $ V_- $ node we can find Vout by using the following equation.

$ \begin{align} i = \frac{V_- - Vout}{8}\\ 3 = \frac{6 - Vout}{8}\\ 24 = 6 - Vout\\ Vout = -18 V\\ \end{align} $

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